Search a number
-
+
20221300997 is a prime number
BaseRepresentation
bin10010110101010010…
…001001000100000101
31221012020221112010222
4102311102021010011
5312403123112442
613142312354125
71314050136212
oct226522110405
957166845128
1020221300997
118637440807
123b040a5945
131ba34ac581
14d9b850b09
157d53d18d2
hex4b5489105

20221300997 has 2 divisors, whose sum is σ = 20221300998. Its totient is φ = 20221300996.

The previous prime is 20221300991. The next prime is 20221301003. The reversal of 20221300997 is 79900312202.

It is a balanced prime because it is at equal distance from previous prime (20221300991) and next prime (20221301003).

It can be written as a sum of positive squares in only one way, i.e., 18787088356 + 1434212641 = 137066^2 + 37871^2 .

It is a cyclic number.

It is not a de Polignac number, because 20221300997 - 218 = 20221038853 is a prime.

It is a super-2 number, since 2×202213009972 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20221300991) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10110650498 + 10110650499.

It is an arithmetic number, because the mean of its divisors is an integer number (10110650499).

Almost surely, 220221300997 is an apocalyptic number.

It is an amenable number.

20221300997 is a deficient number, since it is larger than the sum of its proper divisors (1).

20221300997 is an equidigital number, since it uses as much as digits as its factorization.

20221300997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13608, while the sum is 35.

The spelling of 20221300997 in words is "twenty billion, two hundred twenty-one million, three hundred thousand, nine hundred ninety-seven".