Base | Representation |
---|---|
bin | 10010110101110100… |
… | …111011101101000101 |
3 | 1221012220002212212121 |
4 | 102311310323231011 |
5 | 312412441440232 |
6 | 13143240045541 |
7 | 1314220513111 |
oct | 226564735505 |
9 | 57186085777 |
10 | 20230421317 |
11 | 86415aaa67 |
12 | 3b071638b1 |
13 | 1ba5353902 |
14 | d9cb46741 |
15 | 7d60d3d97 |
hex | 4b5d3bb45 |
20230421317 has 2 divisors, whose sum is σ = 20230421318. Its totient is φ = 20230421316.
The previous prime is 20230421303. The next prime is 20230421353. The reversal of 20230421317 is 71312403202.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10574214561 + 9656206756 = 102831^2 + 98266^2 .
It is a cyclic number.
It is not a de Polignac number, because 20230421317 - 211 = 20230419269 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20230421291 and 20230421300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20230421377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10115210658 + 10115210659.
It is an arithmetic number, because the mean of its divisors is an integer number (10115210659).
Almost surely, 220230421317 is an apocalyptic number.
It is an amenable number.
20230421317 is a deficient number, since it is larger than the sum of its proper divisors (1).
20230421317 is an equidigital number, since it uses as much as digits as its factorization.
20230421317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 20230421317 its reverse (71312403202), we get a palindrome (91542824519).
The spelling of 20230421317 in words is "twenty billion, two hundred thirty million, four hundred twenty-one thousand, three hundred seventeen".
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