Search a number
-
+
20231330331269 is a prime number
BaseRepresentation
bin1001001100110011110010…
…10000011111101010000101
32122122002121012021220221202
410212121321100133222011
510122432231031100034
6111010051141552245
74155444140263361
oct446317120375205
978562535256852
1020231330331269
1164a00715a68a2
122328b73715685
13b39a63492965
144dd2b73222a1
152513e3b1647e
hex12667941fa85

20231330331269 has 2 divisors, whose sum is σ = 20231330331270. Its totient is φ = 20231330331268.

The previous prime is 20231330331229. The next prime is 20231330331271. The reversal of 20231330331269 is 96213303313202.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14498107139044 + 5733223192225 = 3807638^2 + 2394415^2 .

It is a cyclic number.

It is not a de Polignac number, because 20231330331269 - 228 = 20231061895813 is a prime.

It is a super-2 number, since 2×202313303312692 (a number of 27 digits) contains 22 as substring.

Together with 20231330331271, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20231330331229) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10115665165634 + 10115665165635.

It is an arithmetic number, because the mean of its divisors is an integer number (10115665165635).

Almost surely, 220231330331269 is an apocalyptic number.

It is an amenable number.

20231330331269 is a deficient number, since it is larger than the sum of its proper divisors (1).

20231330331269 is an equidigital number, since it uses as much as digits as its factorization.

20231330331269 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 104976, while the sum is 38.

The spelling of 20231330331269 in words is "twenty trillion, two hundred thirty-one billion, three hundred thirty million, three hundred thirty-one thousand, two hundred sixty-nine".