Base | Representation |
---|---|
bin | 11101011110001101100… |
… | …001110000000000001101 |
3 | 21011121122220211211020111 |
4 | 131132031201300000031 |
5 | 231140310312444440 |
6 | 4150224542120021 |
7 | 266215631135635 |
oct | 35361541600015 |
9 | 7147586754214 |
10 | 2025304031245 |
11 | 710a21365000 |
12 | 288626280011 |
13 | 118ca6a7a521 |
14 | 7004d3796c5 |
15 | 37a397084ea |
hex | 1d78d87000d |
2025304031245 has 64 divisors (see below), whose sum is σ = 2700331603200. Its totient is φ = 1458077955840.
The previous prime is 2025304031159. The next prime is 2025304031263. The reversal of 2025304031245 is 5421304035202.
It is not a de Polignac number, because 2025304031245 - 223 = 2025295642637 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 304416339 + ... + 304422991.
It is an arithmetic number, because the mean of its divisors is an integer number (42192681300).
Almost surely, 22025304031245 is an apocalyptic number.
It is an amenable number.
2025304031245 is a deficient number, since it is larger than the sum of its proper divisors (675027571955).
2025304031245 is a wasteful number, since it uses less digits than its factorization.
2025304031245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7147 (or 7125 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 2025304031245 its reverse (5421304035202), we get a palindrome (7446608066447).
The spelling of 2025304031245 in words is "two trillion, twenty-five billion, three hundred four million, thirty-one thousand, two hundred forty-five".
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