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203020112013 = 3185413649931
BaseRepresentation
bin1011110100010011110…
…0010001000010001101
3201102000211011021022220
42331010330101002031
511311241122041023
6233133253325553
720445012323205
oct2750474210215
9642024137286
10203020112013
1179111619044
123341b0368b9
13161b5c25ac4
149b7d241405
15543368c3e3
hex2f44f1108d

203020112013 has 8 divisors (see below), whose sum is σ = 270708156576. Its totient is φ = 135339404400.

The previous prime is 203020111981. The next prime is 203020112023. The reversal of 203020112013 is 310211020302.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 203020112013 - 25 = 203020111981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 203020111983 and 203020112001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (203020112023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1769343 + ... + 1880588.

It is an arithmetic number, because the mean of its divisors is an integer number (33838519572).

Almost surely, 2203020112013 is an apocalyptic number.

It is an amenable number.

203020112013 is a deficient number, since it is larger than the sum of its proper divisors (67688044563).

203020112013 is a wasteful number, since it uses less digits than its factorization.

203020112013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3668475.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 203020112013 its reverse (310211020302), we get a palindrome (513231132315).

The spelling of 203020112013 in words is "two hundred three billion, twenty million, one hundred twelve thousand, thirteen".

Divisors: 1 3 18541 55623 3649931 10949793 67673370671 203020112013