Base | Representation |
---|---|
bin | 11101100010111110000… |
… | …111001010001001001101 |
3 | 21012002212001100210021002 |
4 | 131202332013022021031 |
5 | 231231242003030214 |
6 | 4152432004550045 |
7 | 266456361120353 |
oct | 35427607121115 |
9 | 7162761323232 |
10 | 2030414111309 |
11 | 713103918871 |
12 | 2896116b2325 |
13 | 11960c66ba3c |
14 | 703b5cd37d3 |
15 | 37c381561de |
hex | 1d8be1ca24d |
2030414111309 has 2 divisors, whose sum is σ = 2030414111310. Its totient is φ = 2030414111308.
The previous prime is 2030414111221. The next prime is 2030414111311. The reversal of 2030414111309 is 9031114140302.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2015917228900 + 14496882409 = 1419830^2 + 120403^2 .
It is a cyclic number.
It is not a de Polignac number, because 2030414111309 - 212 = 2030414107213 is a prime.
It is a super-3 number, since 3×20304141113093 (a number of 38 digits) contains 333 as substring.
Together with 2030414111311, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2030414111399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1015207055654 + 1015207055655.
It is an arithmetic number, because the mean of its divisors is an integer number (1015207055655).
Almost surely, 22030414111309 is an apocalyptic number.
It is an amenable number.
2030414111309 is a deficient number, since it is larger than the sum of its proper divisors (1).
2030414111309 is an equidigital number, since it uses as much as digits as its factorization.
2030414111309 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 29.
The spelling of 2030414111309 in words is "two trillion, thirty billion, four hundred fourteen million, one hundred eleven thousand, three hundred nine".
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