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203042445151 = 7132231235661
BaseRepresentation
bin1011110100011001000…
…1011101011101011111
3201102002101011220122011
42331012101131131133
511311312331221101
6233135412132051
720445403210330
oct2750621353537
9642071156564
10203042445151
1179123192287
1233426607027
13161ba745190
149b821b6287
1554355ee751
hex2f4645d75f

203042445151 has 8 divisors (see below), whose sum is σ = 249898394144. Its totient is φ = 160648967520.

The previous prime is 203042445103. The next prime is 203042445157. The reversal of 203042445151 is 151544240302.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-203042445151 is a prime.

It is a super-3 number, since 3×2030424451513 (a number of 35 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (203042445157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1115617740 + ... + 1115617921.

It is an arithmetic number, because the mean of its divisors is an integer number (31237299268).

Almost surely, 2203042445151 is an apocalyptic number.

203042445151 is a deficient number, since it is larger than the sum of its proper divisors (46855948993).

203042445151 is a wasteful number, since it uses less digits than its factorization.

203042445151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2231235681.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 203042445151 its reverse (151544240302), we get a palindrome (354586685453).

The spelling of 203042445151 in words is "two hundred three billion, forty-two million, four hundred forty-five thousand, one hundred fifty-one".

Divisors: 1 7 13 91 2231235661 15618649627 29006063593 203042445151