Base | Representation |
---|---|
bin | 101110001100000101001111… |
… | …100000000011110100011111 |
3 | 222122021000212220001002112021 |
4 | 232030011033200003310133 |
5 | 203111223020403100411 |
6 | 2000013225023121011 |
7 | 60534260351025160 |
oct | 5614051740036437 |
9 | 878230786032467 |
10 | 203140402003231 |
11 | 597aa3a7087140 |
12 | 1a949b79743167 |
13 | 8947099a440b4 |
14 | 38240956b1767 |
15 | 1874234961a71 |
hex | b8c14f803d1f |
203140402003231 has 8 divisors (see below), whose sum is σ = 253265955744384. Its totient is φ = 158291222340120.
The previous prime is 203140402003171. The next prime is 203140402003237. The reversal of 203140402003231 is 132300204041302.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 203140402003231 - 29 = 203140402002719 is a prime.
It is a super-2 number, since 2×2031404020032312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 203140402003196 and 203140402003205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (203140402003237) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1319093519425 + ... + 1319093519578.
It is an arithmetic number, because the mean of its divisors is an integer number (31658244468048).
Almost surely, 2203140402003231 is an apocalyptic number.
203140402003231 is a deficient number, since it is larger than the sum of its proper divisors (50125553741153).
203140402003231 is a wasteful number, since it uses less digits than its factorization.
203140402003231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2638187039021.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 203140402003231 its reverse (132300204041302), we get a palindrome (335440606044533).
The spelling of 203140402003231 in words is "two hundred three trillion, one hundred forty billion, four hundred two million, three thousand, two hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •