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2040213311 is a prime number
BaseRepresentation
bin111100110011011…
…0010111100111111
312021012000120111222
41321212302330333
513134243311221
6534240503555
7101362345523
oct17146627477
95235016458
102040213311
11957713504
1248b31abbb
132668b7016
14154d65d83
15be1a79ab
hex799b2f3f

2040213311 has 2 divisors, whose sum is σ = 2040213312. Its totient is φ = 2040213310.

The previous prime is 2040213281. The next prime is 2040213313. The reversal of 2040213311 is 1133120402.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2040213311 - 26 = 2040213247 is a prime.

Together with 2040213313, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2040213311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2040213313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1020106655 + 1020106656.

It is an arithmetic number, because the mean of its divisors is an integer number (1020106656).

Almost surely, 22040213311 is an apocalyptic number.

2040213311 is a deficient number, since it is larger than the sum of its proper divisors (1).

2040213311 is an equidigital number, since it uses as much as digits as its factorization.

2040213311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 2040213311 is about 45168.7204932794. The cubic root of 2040213311 is about 1268.3093445863.

Adding to 2040213311 its reverse (1133120402), we get a palindrome (3173333713).

The spelling of 2040213311 in words is "two billion, forty million, two hundred thirteen thousand, three hundred eleven".