204040141213 has 4 divisors (see below), whose sum is σ = 204247711008. Its totient is φ = 203832571420.

The previous prime is 204040141211. The next prime is 204040141223. The reversal of 204040141213 is 312141040402.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 312141040402 = 2 ⋅156070520201.

It is a cyclic number.

It is not a de Polignac number, because 204040141213 - 2¹ = 204040141211 is a prime.

It is a super-2 number, since 2×204040141213² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (204040141211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 103783423 + ... + 103785388.

It is an arithmetic number, because the mean of its divisors is an integer number (51061927752).

Almost surely, 2^204040141213 is an apocalyptic number.

It is an amenable number.

204040141213 is a deficient number, since it is larger than the sum of its proper divisors (207569795).

204040141213 is an equidigital number, since it uses as much as digits as its factorization.

204040141213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 207569794.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 204040141213 its reverse (312141040402), we get a palindrome (516181181615).

The spelling of 204040141213 in words is "two hundred four billion, forty million, one hundred forty-one thousand, two hundred thirteen".