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2041400051132 = 221339257693291
BaseRepresentation
bin11101101101001100111…
…011001100010110111100
321020011012200100100120012
4131231030323030112330
5231421241403114012
64201450051442352
7300325540063421
oct35551473142674
97204180310505
102041400051132
11717831122a82
1228b7788b63b8
1311a6706b2750
1470b38d83d48
153817c869622
hex1db4cecc5bc

2041400051132 has 12 divisors (see below), whose sum is σ = 3847253942616. Its totient is φ = 942184638960.

The previous prime is 2041400051113. The next prime is 2041400051179. The reversal of 2041400051132 is 2311500041402.

It is a super-3 number, since 3×20414000511323 (a number of 38 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2041400051098 and 2041400051107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19628846594 + ... + 19628846697.

It is an arithmetic number, because the mean of its divisors is an integer number (320604495218).

Almost surely, 22041400051132 is an apocalyptic number.

It is an amenable number.

2041400051132 is a deficient number, since it is larger than the sum of its proper divisors (1805853891484).

2041400051132 is a wasteful number, since it uses less digits than its factorization.

2041400051132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39257693308 (or 39257693306 counting only the distinct ones).

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 2041400051132 its reverse (2311500041402), we get a palindrome (4352900092534).

The spelling of 2041400051132 in words is "two trillion, forty-one billion, four hundred million, fifty-one thousand, one hundred thirty-two".

Divisors: 1 2 4 13 26 52 39257693291 78515386582 157030773164 510350012783 1020700025566 2041400051132