Base | Representation |
---|---|
bin | 11101101101001100111… |
… | …011001100010110111100 |
3 | 21020011012200100100120012 |
4 | 131231030323030112330 |
5 | 231421241403114012 |
6 | 4201450051442352 |
7 | 300325540063421 |
oct | 35551473142674 |
9 | 7204180310505 |
10 | 2041400051132 |
11 | 717831122a82 |
12 | 28b7788b63b8 |
13 | 11a6706b2750 |
14 | 70b38d83d48 |
15 | 3817c869622 |
hex | 1db4cecc5bc |
2041400051132 has 12 divisors (see below), whose sum is σ = 3847253942616. Its totient is φ = 942184638960.
The previous prime is 2041400051113. The next prime is 2041400051179. The reversal of 2041400051132 is 2311500041402.
It is a super-3 number, since 3×20414000511323 (a number of 38 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2041400051098 and 2041400051107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19628846594 + ... + 19628846697.
It is an arithmetic number, because the mean of its divisors is an integer number (320604495218).
Almost surely, 22041400051132 is an apocalyptic number.
It is an amenable number.
2041400051132 is a deficient number, since it is larger than the sum of its proper divisors (1805853891484).
2041400051132 is a wasteful number, since it uses less digits than its factorization.
2041400051132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39257693308 (or 39257693306 counting only the distinct ones).
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 2041400051132 its reverse (2311500041402), we get a palindrome (4352900092534).
The spelling of 2041400051132 in words is "two trillion, forty-one billion, four hundred million, fifty-one thousand, one hundred thirty-two".
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