Base | Representation |
---|---|
bin | 1001010010101011101100… |
… | …10011110110011001011111 |
3 | 2200100101111221221220111220 |
4 | 10221111312103312121133 |
5 | 10134234034422421421 |
6 | 111242505032344423 |
7 | 4206150236130624 |
oct | 451256623663137 |
9 | 80311457856456 |
10 | 20433144342111 |
11 | 6568714321206 |
12 | 23600b6845113 |
13 | b52ab6569217 |
14 | 508d802c634b |
15 | 2567a64603c6 |
hex | 1295764f665f |
20433144342111 has 12 divisors (see below), whose sum is σ = 28941062575752. Its totient is φ = 12820796449408.
The previous prime is 20433144342059. The next prime is 20433144342133. The reversal of 20433144342111 is 11124344133402.
It is a happy number.
It is not a de Polignac number, because 20433144342111 - 222 = 20433140147807 is a prime.
It is a super-3 number, since 3×204331443421113 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20433144342151) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 11783819400 + ... + 11783821133.
It is an arithmetic number, because the mean of its divisors is an integer number (2411755214646).
Almost surely, 220433144342111 is an apocalyptic number.
20433144342111 is a deficient number, since it is larger than the sum of its proper divisors (8507918233641).
20433144342111 is a wasteful number, since it uses less digits than its factorization.
20433144342111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23567640570 (or 23567640553 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 20433144342111 its reverse (11124344133402), we get a palindrome (31557488475513).
The spelling of 20433144342111 in words is "twenty trillion, four hundred thirty-three billion, one hundred forty-four million, three hundred forty-two thousand, one hundred eleven".
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