Base | Representation |
---|---|
bin | 101110100111111010100111… |
… | …111011111001001001110100 |
3 | 222220000220000022120220010022 |
4 | 232213322213323321021310 |
5 | 203334042320403010200 |
6 | 2004040040452144312 |
7 | 61122413054654222 |
oct | 5647724773711164 |
9 | 886026008526108 |
10 | 205053146141300 |
11 | 5a3776072aa436 |
12 | 1abb880b908098 |
13 | 8a55575b54b22 |
14 | 388c8a78a5b12 |
15 | 18a8d82465885 |
hex | ba7ea7ef9274 |
205053146141300 has 36 divisors (see below), whose sum is σ = 448468991147520. Its totient is φ = 81375421770720.
The previous prime is 205053146141293. The next prime is 205053146141329. The reversal of 205053146141300 is 3141641350502.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8072945810 + ... + 8072971209.
It is an arithmetic number, because the mean of its divisors is an integer number (12457471976320).
Almost surely, 2205053146141300 is an apocalyptic number.
205053146141300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
205053146141300 is an abundant number, since it is smaller than the sum of its proper divisors (243415845006220).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
205053146141300 is a wasteful number, since it uses less digits than its factorization.
205053146141300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16145917160 (or 16145917153 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 205053146141300 its reverse (3141641350502), we get a palindrome (208194787491802).
The spelling of 205053146141300 in words is "two hundred five trillion, fifty-three billion, one hundred forty-six million, one hundred forty-one thousand, three hundred".
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