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21000111021011 is a prime number
BaseRepresentation
bin1001100011001011110000…
…01010000101101111010011
32202100120221211210101100002
410301211320022011233103
510223031211410133021
6112355152352120215
74265131220314223
oct461457012055723
982316854711302
1021000111021011
116767108221731
122431b6683606b
13b943c0581585
145285a7324083
152663db22c50b
hex131978285bd3

21000111021011 has 2 divisors, whose sum is σ = 21000111021012. Its totient is φ = 21000111021010.

The previous prime is 21000111021007. The next prime is 21000111021013. The reversal of 21000111021011 is 11012011100012.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21000111021011 - 22 = 21000111021007 is a prime.

Together with 21000111021013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 21000111020983 and 21000111021001.

It is not a weakly prime, because it can be changed into another prime (21000111021013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10500055510505 + 10500055510506.

It is an arithmetic number, because the mean of its divisors is an integer number (10500055510506).

Almost surely, 221000111021011 is an apocalyptic number.

21000111021011 is a deficient number, since it is larger than the sum of its proper divisors (1).

21000111021011 is an equidigital number, since it uses as much as digits as its factorization.

21000111021011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 21000111021011 its reverse (11012011100012), we get a palindrome (32012122121023).

The spelling of 21000111021011 in words is "twenty-one trillion, one hundred eleven million, twenty-one thousand, eleven".