Base | Representation |
---|---|
bin | 101111110000000100000110… |
… | …110111111100011100101010 |
3 | 1000112120212102211011221000102 |
4 | 233300010012313330130222 |
5 | 210011310244041420242 |
6 | 2022353440510505402 |
7 | 62143542415431113 |
oct | 5760040667743452 |
9 | 1015525384157012 |
10 | 210011131201322 |
11 | 60a09247647700 |
12 | 1b679692b05262 |
13 | 9024c7058b259 |
14 | 39c084321720a |
15 | 1942d1133ae32 |
hex | bf0106dfc72a |
210011131201322 has 12 divisors (see below), whose sum is σ = 346258022105058. Its totient is φ = 95459605091400.
The previous prime is 210011131201303. The next prime is 210011131201351. The reversal of 210011131201322 is 223102131110012.
It can be written as a sum of positive squares in only one way, i.e., 204417333856681 + 5593797344641 = 14297459^2 + 2365121^2 .
It is a junction number, because it is equal to n+sod(n) for n = 210011131201294 and 210011131201303.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 433907295629 + ... + 433907296112.
Almost surely, 2210011131201322 is an apocalyptic number.
210011131201322 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
210011131201322 is a deficient number, since it is larger than the sum of its proper divisors (136246890903736).
210011131201322 is a wasteful number, since it uses less digits than its factorization.
210011131201322 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 867814591765 (or 867814591754 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 210011131201322 its reverse (223102131110012), we get a palindrome (433113262311334).
The spelling of 210011131201322 in words is "two hundred ten trillion, eleven billion, one hundred thirty-one million, two hundred one thousand, three hundred twenty-two".
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