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210011312200031 = 229917079965939
BaseRepresentation
bin101111110000000100010001…
…101010011001100101011111
31000112120212220102202121120022
4233300010101222121211133
5210011311131410400111
62022353510454142355
762143550044046126
oct5760042152314537
91015525812677508
10210011312200031
1160a0932a831711
121b6797236519bb
139024c9bc21894
1439c085d290abd
151942d221902db
hexbf0111a9995f

210011312200031 has 4 divisors (see below), whose sum is σ = 210928392166200. Its totient is φ = 209094232233864.

The previous prime is 210011312199917. The next prime is 210011312200037. The reversal of 210011312200031 is 130002213110012.

210011312200031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 210011312200031 - 218 = 210011311937887 is a prime.

It is a super-2 number, since 2×2100113122000312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 210011312199982 and 210011312200009.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (210011312200037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 458539982741 + ... + 458539983198.

It is an arithmetic number, because the mean of its divisors is an integer number (52732098041550).

Almost surely, 2210011312200031 is an apocalyptic number.

210011312200031 is a deficient number, since it is larger than the sum of its proper divisors (917079966169).

210011312200031 is an equidigital number, since it uses as much as digits as its factorization.

210011312200031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 917079966168.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 210011312200031 its reverse (130002213110012), we get a palindrome (340013525310043).

The spelling of 210011312200031 in words is "two hundred ten trillion, eleven billion, three hundred twelve million, two hundred thousand, thirty-one".

Divisors: 1 229 917079965939 210011312200031