210013131112133 has 4 divisors (see below), whose sum is σ = 213455969327148. Its totient is φ = 206570292897120.

The previous prime is 210013131112123. The next prime is 210013131112151. The reversal of 210013131112133 is 331211131310012.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 30214612355524 + 179798518756609 = 5496782^2 + 13408897^2 .

It is a cyclic number.

It is not a de Polignac number, because 210013131112133 - 2¹² = 210013131108037 is a prime.

It is a super-3 number, since 3×210013131112133³ (a number of 44 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 210013131112099 and 210013131112108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (210013131112123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1721419107416 + ... + 1721419107537.

It is an arithmetic number, because the mean of its divisors is an integer number (53363992331787).

Almost surely, 2^{210013131112133} is an apocalyptic number.

It is an amenable number.

210013131112133 is a deficient number, since it is larger than the sum of its proper divisors (3442838215015).

210013131112133 is an equidigital number, since it uses as much as digits as its factorization.

210013131112133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3442838215014.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 210013131112133 its reverse (331211131310012), we get a palindrome (541224262422145).

The spelling of 210013131112133 in words is "two hundred ten trillion, thirteen billion, one hundred thirty-one million, one hundred twelve thousand, one hundred thirty-three".