21001333000031 has 2 divisors, whose sum is σ = 21001333000032. Its totient is φ = 21001333000030.

The previous prime is 21001332999943. The next prime is 21001333000033. The reversal of 21001333000031 is 13000033310012.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21001333000031 - 2³⁸ = 20726455093087 is a prime.

It is a super-2 number, since 2×21001333000031² (a number of 27 digits) contains 22 as substring.

Together with 21001333000033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 21001332999973 and 21001333000009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21001333000033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10500666500015 + 10500666500016.

It is an arithmetic number, because the mean of its divisors is an integer number (10500666500016).

Almost surely, 2^{21001333000031} is an apocalyptic number.

21001333000031 is a deficient number, since it is larger than the sum of its proper divisors (1).

21001333000031 is an equidigital number, since it uses as much as digits as its factorization.

21001333000031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 21001333000031 its reverse (13000033310012), we get a palindrome (34001366310043).

The spelling of 21001333000031 in words is "twenty-one trillion, one billion, three hundred thirty-three million, thirty-one", and thus it is an aban number.