Base | Representation |
---|---|
bin | 11110100100101110001… |
… | …000100011011100100111 |
3 | 21102212002012122000202020 |
4 | 132210232020203130213 |
5 | 233410333312031043 |
6 | 4245105252114223 |
7 | 304536026566155 |
oct | 36445610433447 |
9 | 7385065560666 |
10 | 2101013002023 |
11 | 740042080341 |
12 | 29b235005973 |
13 | 123180bb40a0 |
14 | 739922843d5 |
15 | 399bb115e83 |
hex | 1e92e223727 |
2101013002023 has 16 divisors (see below), whose sum is σ = 3194300311776. Its totient is φ = 1216876308480.
The previous prime is 2101013002019. The next prime is 2101013002037. The reversal of 2101013002023 is 3202003101012.
It is not a de Polignac number, because 2101013002023 - 22 = 2101013002019 is a prime.
It is a super-4 number, since 4×21010130020234 (a number of 50 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2101013001993 and 2101013002011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2101013002043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1584473698 + ... + 1584475023.
It is an arithmetic number, because the mean of its divisors is an integer number (199643769486).
Almost surely, 22101013002023 is an apocalyptic number.
2101013002023 is a deficient number, since it is larger than the sum of its proper divisors (1093287309753).
2101013002023 is a wasteful number, since it uses less digits than its factorization.
2101013002023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3168948754.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 2101013002023 its reverse (3202003101012), we get a palindrome (5303016103035).
The spelling of 2101013002023 in words is "two trillion, one hundred one billion, thirteen million, two thousand, twenty-three".
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