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2101013002023 = 313173168948721
BaseRepresentation
bin11110100100101110001…
…000100011011100100111
321102212002012122000202020
4132210232020203130213
5233410333312031043
64245105252114223
7304536026566155
oct36445610433447
97385065560666
102101013002023
11740042080341
1229b235005973
13123180bb40a0
14739922843d5
15399bb115e83
hex1e92e223727

2101013002023 has 16 divisors (see below), whose sum is σ = 3194300311776. Its totient is φ = 1216876308480.

The previous prime is 2101013002019. The next prime is 2101013002037. The reversal of 2101013002023 is 3202003101012.

It is not a de Polignac number, because 2101013002023 - 22 = 2101013002019 is a prime.

It is a super-4 number, since 4×21010130020234 (a number of 50 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2101013001993 and 2101013002011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2101013002043) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1584473698 + ... + 1584475023.

It is an arithmetic number, because the mean of its divisors is an integer number (199643769486).

Almost surely, 22101013002023 is an apocalyptic number.

2101013002023 is a deficient number, since it is larger than the sum of its proper divisors (1093287309753).

2101013002023 is a wasteful number, since it uses less digits than its factorization.

2101013002023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3168948754.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 2101013002023 its reverse (3202003101012), we get a palindrome (5303016103035).

The spelling of 2101013002023 in words is "two trillion, one hundred one billion, thirteen million, two thousand, twenty-three".

Divisors: 1 3 13 17 39 51 221 663 3168948721 9506846163 41196333373 53872128257 123589000119 161616384771 700337667341 2101013002023