Base | Representation |
---|---|
bin | 1100001110101110011… |
… | …0101010001000011101 |
3 | 202002100000022101002011 |
4 | 3003223212222020131 |
5 | 11420301432210023 |
6 | 240305044231221 |
7 | 21115515550255 |
oct | 3035346521035 |
9 | 662300271064 |
10 | 210111210013 |
11 | 81120333a11 |
12 | 3487999b511 |
13 | 16a76076693 |
14 | a252d12965 |
15 | 56eae9d50d |
hex | 30eb9aa21d |
210111210013 has 2 divisors, whose sum is σ = 210111210014. Its totient is φ = 210111210012.
The previous prime is 210111209993. The next prime is 210111210103. The reversal of 210111210013 is 310012111012.
It is a happy number.
210111210013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
Together with next prime (210111210103) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 186315679449 + 23795530564 = 431643^2 + 154258^2 .
It is a cyclic number.
It is not a de Polignac number, because 210111210013 - 233 = 201521275421 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 210111209975 and 210111210002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (210111210613) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105055605006 + 105055605007.
It is an arithmetic number, because the mean of its divisors is an integer number (105055605007).
Almost surely, 2210111210013 is an apocalyptic number.
It is an amenable number.
210111210013 is a deficient number, since it is larger than the sum of its proper divisors (1).
210111210013 is an equidigital number, since it uses as much as digits as its factorization.
210111210013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 210111210013 its reverse (310012111012), we get a palindrome (520123321025).
Subtracting 210111210013 from its reverse (310012111012), we obtain a palindrome (99900900999).
The spelling of 210111210013 in words is "two hundred ten billion, one hundred eleven million, two hundred ten thousand, thirteen".
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