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21013354351 = 111910304941
BaseRepresentation
bin10011100100011111…
…100101011101101111
32000020110100000002101
4103210133211131233
5321013404314401
613353045035531
71342505364523
oct234437453557
960213300071
1021013354351
118a03544160
1240a53b5ba7
131c9b60c3b2
141034b0bd83
1582ebd9101
hex4e47e576f

21013354351 has 4 divisors (see below), whose sum is σ = 22923659304. Its totient is φ = 19103049400.

The previous prime is 21013354319. The next prime is 21013354379. The reversal of 21013354351 is 15345331012.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21013354351 - 25 = 21013354319 is a prime.

It is a super-2 number, since 2×210133543512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21013354301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 955152460 + ... + 955152481.

It is an arithmetic number, because the mean of its divisors is an integer number (5730914826).

Almost surely, 221013354351 is an apocalyptic number.

21013354351 is a deficient number, since it is larger than the sum of its proper divisors (1910304953).

21013354351 is a wasteful number, since it uses less digits than its factorization.

21013354351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1910304952.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 21013354351 its reverse (15345331012), we get a palindrome (36358685363).

The spelling of 21013354351 in words is "twenty-one billion, thirteen million, three hundred fifty-four thousand, three hundred fifty-one".

Divisors: 1 11 1910304941 21013354351