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21041331335 = 54208266267
BaseRepresentation
bin10011100110001010…
…010011110010000111
32000022101222101021222
4103212022103302013
5321043040100320
613355524430555
71343265236213
oct234612236207
960271871258
1021041331335
118a18312732
1240b284845b
131ca435661b
141038711943
158323b3825
hex4e6293c87

21041331335 has 4 divisors (see below), whose sum is σ = 25249597608. Its totient is φ = 16833065064.

The previous prime is 21041331331. The next prime is 21041331349. The reversal of 21041331335 is 53313314012.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21041331335 - 22 = 21041331331 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21041331331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2104133129 + ... + 2104133138.

It is an arithmetic number, because the mean of its divisors is an integer number (6312399402).

Almost surely, 221041331335 is an apocalyptic number.

21041331335 is a deficient number, since it is larger than the sum of its proper divisors (4208266273).

21041331335 is an equidigital number, since it uses as much as digits as its factorization.

21041331335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4208266272.

The product of its (nonzero) digits is 3240, while the sum is 26.

Adding to 21041331335 its reverse (53313314012), we get a palindrome (74354645347).

The spelling of 21041331335 in words is "twenty-one billion, forty-one million, three hundred thirty-one thousand, three hundred thirty-five".

Divisors: 1 5 4208266267 21041331335