Search a number
-
+
2104434131 = 17214948871
BaseRepresentation
bin111110101101111…
…0001110111010011
312102122212022220212
41331123301313103
513302213343011
6544453154335
7103102252322
oct17533616723
95378768825
102104434131
1198a997568
124a892b9ab
13276cb11c7
1415d6c20b9
15c4b4108b
hex7d6f1dd3

2104434131 has 12 divisors (see below), whose sum is σ = 2250555600. Its totient is φ = 1967310720.

The previous prime is 2104434127. The next prime is 2104434133. The reversal of 2104434131 is 1314344012.

It is not a de Polignac number, because 2104434131 - 22 = 2104434127 is a prime.

It is a super-2 number, since 2×21044341312 = 8857286023435450322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2104434097 and 2104434106.

It is not an unprimeable number, because it can be changed into a prime (2104434133) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 18626 + ... + 67496.

It is an arithmetic number, because the mean of its divisors is an integer number (187546300).

Almost surely, 22104434131 is an apocalyptic number.

2104434131 is a deficient number, since it is larger than the sum of its proper divisors (146121469).

2104434131 is a wasteful number, since it uses less digits than its factorization.

2104434131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49054 (or 49037 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

The square root of 2104434131 is about 45874.1117734175. Note that the first 3 decimals coincide. The cubic root of 2104434131 is about 1281.4798418012.

Adding to 2104434131 its reverse (1314344012), we get a palindrome (3418778143).

The spelling of 2104434131 in words is "two billion, one hundred four million, four hundred thirty-four thousand, one hundred thirty-one".

Divisors: 1 17 149 289 2533 43061 48871 830807 7281779 14123719 123790243 2104434131