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2110000012112 = 24131875000757
BaseRepresentation
bin11110101101000101110…
…011010001101101010000
321110201021112021102221202
4132231011303101231100
5234032240000341422
64253153131010332
7305304524115566
oct36550563215520
97421245242852
102110000012112
11743933aaa003
122a0b228999a8
13123c83a66935
14741a5a77a36
1539d450c8b92
hex1eb45cd1b50

2110000012112 has 10 divisors (see below), whose sum is σ = 4088125023498. Its totient is φ = 1055000006048.

The previous prime is 2110000012069. The next prime is 2110000012177. The reversal of 2110000012112 is 2112100000112.

It can be written as a sum of positive squares in only one way, i.e., 2076204337216 + 33795674896 = 1440904^2 + 183836^2 .

It is a super-3 number, since 3×21100000121123 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 2110000012093 and 2110000012102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65937500363 + ... + 65937500394.

Almost surely, 22110000012112 is an apocalyptic number.

It is an amenable number.

2110000012112 is a deficient number, since it is larger than the sum of its proper divisors (1978125011386).

2110000012112 is a wasteful number, since it uses less digits than its factorization.

2110000012112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131875000765 (or 131875000759 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 2110000012112 its reverse (2112100000112), we get a palindrome (4222100012224).

The spelling of 2110000012112 in words is "two trillion, one hundred ten billion, twelve thousand, one hundred twelve".

Divisors: 1 2 4 8 16 131875000757 263750001514 527500003028 1055000006056 2110000012112