Base | Representation |
---|---|
bin | 11110101101000101110… |
… | …011010001101101010000 |
3 | 21110201021112021102221202 |
4 | 132231011303101231100 |
5 | 234032240000341422 |
6 | 4253153131010332 |
7 | 305304524115566 |
oct | 36550563215520 |
9 | 7421245242852 |
10 | 2110000012112 |
11 | 743933aaa003 |
12 | 2a0b228999a8 |
13 | 123c83a66935 |
14 | 741a5a77a36 |
15 | 39d450c8b92 |
hex | 1eb45cd1b50 |
2110000012112 has 10 divisors (see below), whose sum is σ = 4088125023498. Its totient is φ = 1055000006048.
The previous prime is 2110000012069. The next prime is 2110000012177. The reversal of 2110000012112 is 2112100000112.
It can be written as a sum of positive squares in only one way, i.e., 2076204337216 + 33795674896 = 1440904^2 + 183836^2 .
It is a super-3 number, since 3×21100000121123 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 2110000012093 and 2110000012102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65937500363 + ... + 65937500394.
Almost surely, 22110000012112 is an apocalyptic number.
It is an amenable number.
2110000012112 is a deficient number, since it is larger than the sum of its proper divisors (1978125011386).
2110000012112 is a wasteful number, since it uses less digits than its factorization.
2110000012112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 131875000765 (or 131875000759 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 2110000012112 its reverse (2112100000112), we get a palindrome (4222100012224).
The spelling of 2110000012112 in words is "two trillion, one hundred ten billion, twelve thousand, one hundred twelve".
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