Base | Representation |
---|---|
bin | 1100010010000010110… |
… | …0110000101011000111 |
3 | 202011122002111022010101 |
4 | 3010200230300223013 |
5 | 11424113003031434 |
6 | 240533305104531 |
7 | 21146553265636 |
oct | 3044054605307 |
9 | 664562438111 |
10 | 211002002119 |
11 | 81538147237 |
12 | 34a88188147 |
13 | 16b88797bbc |
14 | a2d935351d |
15 | 574e2abb14 |
hex | 3120b30ac7 |
211002002119 has 2 divisors, whose sum is σ = 211002002120. Its totient is φ = 211002002118.
The previous prime is 211002002059. The next prime is 211002002149. The reversal of 211002002119 is 911200200112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211002002119 - 211 = 211002000071 is a prime.
It is a super-2 number, since 2×2110020021192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211002002096 and 211002002105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211002002149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105501001059 + 105501001060.
It is an arithmetic number, because the mean of its divisors is an integer number (105501001060).
Almost surely, 2211002002119 is an apocalyptic number.
211002002119 is a deficient number, since it is larger than the sum of its proper divisors (1).
211002002119 is an equidigital number, since it uses as much as digits as its factorization.
211002002119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
The spelling of 211002002119 in words is "two hundred eleven billion, two million, two thousand, one hundred nineteen".
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