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2110031311 is a prime number
BaseRepresentation
bin111110111000100…
…1000010111001111
312110001101200210211
41331301020113033
513310132000221
6545213143251
7103200653533
oct17561102717
95401350724
102110031311
1199306a833
124aa78ab27
132781c0a4b
1416033bbc3
15c53996e1
hex7dc485cf

2110031311 has 2 divisors, whose sum is σ = 2110031312. Its totient is φ = 2110031310.

The previous prime is 2110031309. The next prime is 2110031353. The reversal of 2110031311 is 1131300112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2110031311 - 21 = 2110031309 is a prime.

Together with 2110031309, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 2110031291 and 2110031300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2110031411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055015655 + 1055015656.

It is an arithmetic number, because the mean of its divisors is an integer number (1055015656).

Almost surely, 22110031311 is an apocalyptic number.

2110031311 is a deficient number, since it is larger than the sum of its proper divisors (1).

2110031311 is an equidigital number, since it uses as much as digits as its factorization.

2110031311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 2110031311 is about 45935.0771306634. The cubic root of 2110031311 is about 1282.6149567066.

Adding to 2110031311 its reverse (1131300112), we get a palindrome (3241331423).

The spelling of 2110031311 in words is "two billion, one hundred ten million, thirty-one thousand, three hundred eleven".