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211010020214111 is a prime number
BaseRepresentation
bin101111111110100110011001…
…010011001000010101011111
31000200010100202010002100112222
4233332212121103020111133
5210124142010133322421
62024440355353015555
762305654003103306
oct5776463123102537
91020110663070488
10211010020214111
1161263935433448
121b7bb1a49b45bb
13909820c62a0c1
143a16d21ca143d
15195dcc529acab
hexbfe9994c855f

211010020214111 has 2 divisors, whose sum is σ = 211010020214112. Its totient is φ = 211010020214110.

The previous prime is 211010020214069. The next prime is 211010020214113. The reversal of 211010020214111 is 111412020010112.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211010020214111 is a prime.

Together with 211010020214113, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 211010020214111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211010020214113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105505010107055 + 105505010107056.

It is an arithmetic number, because the mean of its divisors is an integer number (105505010107056).

Almost surely, 2211010020214111 is an apocalyptic number.

211010020214111 is a deficient number, since it is larger than the sum of its proper divisors (1).

211010020214111 is an equidigital number, since it uses as much as digits as its factorization.

211010020214111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 211010020214111 its reverse (111412020010112), we get a palindrome (322422040224223).

The spelling of 211010020214111 in words is "two hundred eleven trillion, ten billion, twenty million, two hundred fourteen thousand, one hundred eleven".