Base | Representation |
---|---|
bin | 1001100110001001110000… |
… | …11111100011001110010011 |
3 | 2202201100021011200010212121 |
4 | 10303010320133203032103 |
5 | 10231214121230320313 |
6 | 112514103040035111 |
7 | 4305402154332304 |
oct | 463047037431623 |
9 | 82640234603777 |
10 | 21102122120083 |
11 | 67a63a5895284 |
12 | 2449896002a97 |
13 | ba0bc9923264 |
14 | 52d4c34cc7ab |
15 | 268dabcbd28d |
hex | 1331387e3393 |
21102122120083 has 2 divisors, whose sum is σ = 21102122120084. Its totient is φ = 21102122120082.
The previous prime is 21102122120081. The next prime is 21102122120159. The reversal of 21102122120083 is 38002122120112.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21102122120083 - 21 = 21102122120081 is a prime.
Together with 21102122120081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (21102122120081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10551061060041 + 10551061060042.
It is an arithmetic number, because the mean of its divisors is an integer number (10551061060042).
Almost surely, 221102122120083 is an apocalyptic number.
21102122120083 is a deficient number, since it is larger than the sum of its proper divisors (1).
21102122120083 is an equidigital number, since it uses as much as digits as its factorization.
21102122120083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 21102122120083 its reverse (38002122120112), we get a palindrome (59104244240195).
The spelling of 21102122120083 in words is "twenty-one trillion, one hundred two billion, one hundred twenty-two million, one hundred twenty thousand, eighty-three".
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