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211040133 = 370346711
BaseRepresentation
bin11001001010000…
…11011110000101
3112201002221122020
430211003132011
5413011241013
632535153353
75141545233
oct1445033605
9481087566
10211040133
11a9143637
125a815859
1334951425
1420057953
15137da623
hexc943785

211040133 has 4 divisors (see below), whose sum is σ = 281386848. Its totient is φ = 140693420.

The previous prime is 211040131. The next prime is 211040149. The reversal of 211040133 is 331040112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211040133 - 21 = 211040131 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211040131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35173353 + ... + 35173358.

It is an arithmetic number, because the mean of its divisors is an integer number (70346712).

Almost surely, 2211040133 is an apocalyptic number.

It is an amenable number.

211040133 is a deficient number, since it is larger than the sum of its proper divisors (70346715).

211040133 is an equidigital number, since it uses as much as digits as its factorization.

211040133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70346714.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 211040133 is about 14527.2204154821. The cubic root of 211040133 is about 595.3719238606.

Adding to 211040133 its reverse (331040112), we get a palindrome (542080245).

The spelling of 211040133 in words is "two hundred eleven million, forty thousand, one hundred thirty-three".

Divisors: 1 3 70346711 211040133