Base | Representation |
---|---|
bin | 1100010010001101001… |
… | …0111000110010001101 |
3 | 202011202010102211021222 |
4 | 3010203102320302031 |
5 | 11424210130114440 |
6 | 240541502333125 |
7 | 21150622405214 |
oct | 3044322706215 |
9 | 664663384258 |
10 | 211045551245 |
11 | 8155a791351 |
12 | 34a9a88a1a5 |
13 | 16b94805009 |
14 | a30104c07b |
15 | 57530102b5 |
hex | 31234b8c8d |
211045551245 has 4 divisors (see below), whose sum is σ = 253254661500. Its totient is φ = 168836440992.
The previous prime is 211045551209. The next prime is 211045551253. The reversal of 211045551245 is 542155540112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 126748816324 + 84296734921 = 356018^2 + 290339^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211045551245 is a prime.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21104555120 + ... + 21104555129.
It is an arithmetic number, because the mean of its divisors is an integer number (63313665375).
Almost surely, 2211045551245 is an apocalyptic number.
It is an amenable number.
211045551245 is a deficient number, since it is larger than the sum of its proper divisors (42209110255).
211045551245 is an equidigital number, since it uses as much as digits as its factorization.
211045551245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42209110254.
The product of its (nonzero) digits is 40000, while the sum is 35.
The spelling of 211045551245 in words is "two hundred eleven billion, forty-five million, five hundred fifty-one thousand, two hundred forty-five".
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