Base | Representation |
---|---|
bin | 1100010010011100100… |
… | …1001000001111111101 |
3 | 202011220121220100022011 |
4 | 3010213021020033331 |
5 | 11424323141231023 |
6 | 240552130051221 |
7 | 21152335154656 |
oct | 3044711101775 |
9 | 664817810264 |
10 | 211110102013 |
11 | 81593170298 |
12 | 34ab8419b11 |
13 | 16ba4cb6435 |
14 | a30985252d |
15 | 5758a1150d |
hex | 31272483fd |
211110102013 has 4 divisors (see below), whose sum is σ = 211155380128. Its totient is φ = 211064823900.
The previous prime is 211110101987. The next prime is 211110102029. The reversal of 211110102013 is 310201011112.
It is a happy number.
211110102013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211110102013 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 211110101984 and 211110102002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211110102713) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22632063 + ... + 22641388.
It is an arithmetic number, because the mean of its divisors is an integer number (52788845032).
Almost surely, 2211110102013 is an apocalyptic number.
It is an amenable number.
211110102013 is a deficient number, since it is larger than the sum of its proper divisors (45278115).
211110102013 is an equidigital number, since it uses as much as digits as its factorization.
211110102013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45278114.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 211110102013 its reverse (310201011112), we get a palindrome (521311113125).
Subtracting 211110102013 from its reverse (310201011112), we obtain a palindrome (99090909099).
The spelling of 211110102013 in words is "two hundred eleven billion, one hundred ten million, one hundred two thousand, thirteen".
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