Base | Representation |
---|---|
bin | 10011101010010101… |
… | …010011011000100011 |
3 | 2000111021200021122021 |
4 | 103222111103120203 |
5 | 321213444302042 |
6 | 13410504522311 |
7 | 1345105164106 |
oct | 235225233043 |
9 | 60437607567 |
10 | 21111322147 |
11 | 8a53877883 |
12 | 4112180397 |
13 | 1cb59c0bc6 |
14 | 1043b3073d |
15 | 8385db867 |
hex | 4ea553623 |
21111322147 has 2 divisors, whose sum is σ = 21111322148. Its totient is φ = 21111322146.
The previous prime is 21111322129. The next prime is 21111322151. The reversal of 21111322147 is 74122311112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21111322147 is a prime.
It is not a weakly prime, because it can be changed into another prime (21111322117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10555661073 + 10555661074.
It is an arithmetic number, because the mean of its divisors is an integer number (10555661074).
Almost surely, 221111322147 is an apocalyptic number.
21111322147 is a deficient number, since it is larger than the sum of its proper divisors (1).
21111322147 is an equidigital number, since it uses as much as digits as its factorization.
21111322147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 672, while the sum is 25.
Adding to 21111322147 its reverse (74122311112), we get a palindrome (95233633259).
The spelling of 21111322147 in words is "twenty-one billion, one hundred eleven million, three hundred twenty-two thousand, one hundred forty-seven".
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