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2111200102127 is a prime number
BaseRepresentation
bin11110101110001101010…
…101010000011011101111
321110211101011110022222002
4132232031111100123233
5234042214211232002
64253512201042515
7305346335530364
oct36561525203357
97424334408862
102111200102127
1174439a467436
122a11b878643b
1312411559007c
147427b1cc46b
1539db5631002
hex1eb8d5506ef

2111200102127 has 2 divisors, whose sum is σ = 2111200102128. Its totient is φ = 2111200102126.

The previous prime is 2111200102111. The next prime is 2111200102129. The reversal of 2111200102127 is 7212010021112.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2111200102127 - 24 = 2111200102111 is a prime.

Together with 2111200102129, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2111200102099 and 2111200102108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2111200102129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055600051063 + 1055600051064.

It is an arithmetic number, because the mean of its divisors is an integer number (1055600051064).

Almost surely, 22111200102127 is an apocalyptic number.

2111200102127 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111200102127 is an equidigital number, since it uses as much as digits as its factorization.

2111200102127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 112, while the sum is 20.

Adding to 2111200102127 its reverse (7212010021112), we get a palindrome (9323210123239).

The spelling of 2111200102127 in words is "two trillion, one hundred eleven billion, two hundred million, one hundred two thousand, one hundred twenty-seven".