Base | Representation |
---|---|
bin | 110000000000001110111001… |
… | …000011010110111000100111 |
3 | 1000200112002100122201201112112 |
4 | 300000032321003112320213 |
5 | 210133011302324200012 |
6 | 2025004113200511235 |
7 | 62320035322306211 |
oct | 6000167103267047 |
9 | 1020462318651475 |
10 | 211122222100007 |
11 | 612a7482480a69 |
12 | 1b818a9901b51b |
13 | 90a5981068b6a |
14 | 3a1c5276935b1 |
15 | 1961b90834122 |
hex | c003b90d6e27 |
211122222100007 has 2 divisors, whose sum is σ = 211122222100008. Its totient is φ = 211122222100006.
The previous prime is 211122222099977. The next prime is 211122222100033. The reversal of 211122222100007 is 700001222221112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211122222100007 is a prime.
It is a super-2 number, since 2×2111222221000072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211122222100607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105561111050003 + 105561111050004.
It is an arithmetic number, because the mean of its divisors is an integer number (105561111050004).
Almost surely, 2211122222100007 is an apocalyptic number.
211122222100007 is a deficient number, since it is larger than the sum of its proper divisors (1).
211122222100007 is an equidigital number, since it uses as much as digits as its factorization.
211122222100007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448, while the sum is 23.
Adding to 211122222100007 its reverse (700001222221112), we get a palindrome (911123444321119).
The spelling of 211122222100007 in words is "two hundred eleven trillion, one hundred twenty-two billion, two hundred twenty-two million, one hundred thousand, seven".
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