Base | Representation |
---|---|
bin | 11110101110010011010… |
… | …010110111110001000100 |
3 | 21110211122010200210021012 |
4 | 132232103102313301010 |
5 | 234042420313440400 |
6 | 4253530133141352 |
7 | 305351662041314 |
oct | 36562322676104 |
9 | 7424563623235 |
10 | 2111300140100 |
11 | 744440984448 |
12 | 2a122618a858 |
13 | 124130217c38 |
14 | 7428a5cd444 |
15 | 39dbe2e1d35 |
hex | 1eb934b7c44 |
2111300140100 has 36 divisors (see below), whose sum is σ = 4667965113924. Its totient is φ = 828585713280.
The previous prime is 2111300140067. The next prime is 2111300140111. The reversal of 2111300140100 is 10410031112.
It can be written as a sum of positive squares in 6 ways, for example, as 18480771136 + 2092819368964 = 135944^2 + 1446658^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 199173959 + ... + 199184558.
It is an arithmetic number, because the mean of its divisors is an integer number (129665697609).
Almost surely, 22111300140100 is an apocalyptic number.
2111300140100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2111300140100 is an abundant number, since it is smaller than the sum of its proper divisors (2556664973824).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2111300140100 is a wasteful number, since it uses less digits than its factorization.
2111300140100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 398358584 (or 398358577 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 2111300140100 its reverse (10410031112), we get a palindrome (2121710171212).
The spelling of 2111300140100 in words is "two trillion, one hundred eleven billion, three hundred million, one hundred forty thousand, one hundred".
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