Base | Representation |
---|---|
bin | 10011101010011100… |
… | …001101010001000111 |
3 | 2000111102002020102200 |
4 | 103222130031101013 |
5 | 321214430211403 |
6 | 13411011405543 |
7 | 1345126443000 |
oct | 235234152107 |
9 | 60442066380 |
10 | 21113132103 |
11 | 8a548a3708 |
12 | 41128b38b3 |
13 | 1cb61a599b |
14 | 10440821a7 |
15 | 838847ca3 |
hex | 4ea70d447 |
21113132103 has 24 divisors (see below), whose sum is σ = 35564724000. Its totient is φ = 12064645152.
The previous prime is 21113132093. The next prime is 21113132107. The reversal of 21113132103 is 30123131112.
21113132103 is a `hidden beast` number, since 211 + 131 + 321 + 0 + 3 = 666.
It is not a de Polignac number, because 21113132103 - 25 = 21113132071 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21113132107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3416598 + ... + 3422771.
It is an arithmetic number, because the mean of its divisors is an integer number (1481863500).
Almost surely, 221113132103 is an apocalyptic number.
21113132103 is a deficient number, since it is larger than the sum of its proper divisors (14451591897).
21113132103 is an equidigital number, since it uses as much as digits as its factorization.
21113132103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6839396 (or 6839379 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 21113132103 its reverse (30123131112), we get a palindrome (51236263215).
Subtracting 21113132103 from its reverse (30123131112), we obtain a palindrome (9009999009).
The spelling of 21113132103 in words is "twenty-one billion, one hundred thirteen million, one hundred thirty-two thousand, one hundred three".
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