2111313310000 has 50 divisors (see below), whose sum is σ = 5111700679052. Its totient is φ = 844525320000.

The previous prime is 2111313309991. The next prime is 2111313310019. The reversal of 2111313310000 is 133131112.

It is a tau number, because it is divible by the number of its divisors (50).

It is a super-2 number, since 2×2111313310000² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is an unprimeable number.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 105555666 + ... + 105575665.

Almost surely, 2^{2111313310000} is an apocalyptic number.

2111313310000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

2111313310000 is an abundant number, since it is smaller than the sum of its proper divisors (3000387369052).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2111313310000 is an equidigital number, since it uses as much as digits as its factorization.

2111313310000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 211131359 (or 211131338 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 2111313310000 its reverse (133131112), we get a palindrome (2111446441112).

The spelling of 2111313310000 in words is "two trillion, one hundred eleven billion, three hundred thirteen million, three hundred ten thousand".