Base | Representation |
---|---|
bin | 10011101010011111… |
… | …100111010100011001 |
3 | 2000111110202121120212 |
4 | 103222133213110121 |
5 | 321220142301431 |
6 | 13411042500505 |
7 | 1345140152621 |
oct | 235237472431 |
9 | 60443677525 |
10 | 21114025241 |
11 | 8a55353741 |
12 | 4113064735 |
13 | 1cb642937a |
14 | 1044235881 |
15 | 83897272b |
hex | 4ea7e7519 |
21114025241 has 2 divisors, whose sum is σ = 21114025242. Its totient is φ = 21114025240.
The previous prime is 21114025201. The next prime is 21114025243. The reversal of 21114025241 is 14252041112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20115465241 + 998560000 = 141829^2 + 31600^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21114025241 is a prime.
It is a Sophie Germain prime.
Together with 21114025243, it forms a pair of twin primes.
It is a Chen prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (21114025243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10557012620 + 10557012621.
It is an arithmetic number, because the mean of its divisors is an integer number (10557012621).
Almost surely, 221114025241 is an apocalyptic number.
It is an amenable number.
21114025241 is a deficient number, since it is larger than the sum of its proper divisors (1).
21114025241 is an equidigital number, since it uses as much as digits as its factorization.
21114025241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 640, while the sum is 23.
Adding to 21114025241 its reverse (14252041112), we get a palindrome (35366066353).
The spelling of 21114025241 in words is "twenty-one billion, one hundred fourteen million, twenty-five thousand, two hundred forty-one".
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