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2111412004013 = 131451111934051
BaseRepresentation
bin11110101110011001111…
…101100110010010101101
321110211220221012001201002
4132232121331212102231
5234043132433112023
64253545210530045
7305354520625214
oct36563175462255
97424827161632
102111412004013
11744499039464
122a1257736925
1312414a4537c0
147429b3cc07b
1539dc903bb28
hex1eb99f664ad

2111412004013 has 8 divisors (see below), whose sum is σ = 2275395409056. Its totient is φ = 1947652470000.

The previous prime is 2111412003983. The next prime is 2111412004049. The reversal of 2111412004013 is 3104002141112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2111412004013 - 236 = 2042692527277 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111412004613) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55948163 + ... + 55985888.

It is an arithmetic number, because the mean of its divisors is an integer number (284424426132).

Almost surely, 22111412004013 is an apocalyptic number.

It is an amenable number.

2111412004013 is a deficient number, since it is larger than the sum of its proper divisors (163983405043).

2111412004013 is a wasteful number, since it uses less digits than its factorization.

2111412004013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 111935515.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 2111412004013 its reverse (3104002141112), we get a palindrome (5215414145125).

The spelling of 2111412004013 in words is "two trillion, one hundred eleven billion, four hundred twelve million, four thousand, thirteen".

Divisors: 1 13 1451 18863 111934051 1455142663 162416308001 2111412004013