Base | Representation |
---|---|
bin | 1100010010100110100… |
… | …0111101010101001111 |
3 | 202012000112201222222212 |
4 | 3010221220331111033 |
5 | 11424414403002320 |
6 | 241000224101035 |
7 | 21153354250343 |
oct | 3045150752517 |
9 | 665015658885 |
10 | 211152000335 |
11 | 81604888101 |
12 | 34b0a46477b |
13 | 16bb0896043 |
14 | a31123b623 |
15 | 575c53a9c5 |
hex | 3129a3d54f |
211152000335 has 32 divisors (see below), whose sum is σ = 257611200000. Its totient is φ = 166128299136.
The previous prime is 211152000259. The next prime is 211152000343. The reversal of 211152000335 is 533000251112.
It is a happy number.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211152000335 is a prime.
It is a super-2 number, since 2×2111520003352 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 211152000335.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 124279316 + ... + 124281014.
It is an arithmetic number, because the mean of its divisors is an integer number (8050350000).
Almost surely, 2211152000335 is an apocalyptic number.
211152000335 is a deficient number, since it is larger than the sum of its proper divisors (46459199665).
211152000335 is a wasteful number, since it uses less digits than its factorization.
211152000335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3375.
The product of its (nonzero) digits is 900, while the sum is 23.
Adding to 211152000335 its reverse (533000251112), we get a palindrome (744152251447).
The spelling of 211152000335 in words is "two hundred eleven billion, one hundred fifty-two million, three hundred thirty-five", and thus it is an aban number.
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