Base | Representation |
---|---|
bin | 110000000001011001011000… |
… | …001110111001000000000000 |
3 | 1000200210201210121020022010221 |
4 | 300001121120032321000000 |
5 | 210140314102220041000 |
6 | 2025104541402032424 |
7 | 62325566312221561 |
oct | 6001313016710000 |
9 | 1020721717208127 |
10 | 211202202112000 |
11 | 61328395075830 |
12 | 1b83049a1a8714 |
13 | 90b0388cc2b48 |
14 | 3a22353908168 |
15 | 1963cc21a561a |
hex | c016583b9000 |
211202202112000 has 416 divisors, whose sum is σ = 580708969296768. Its totient is φ = 76040192000000.
The previous prime is 211202202111991. The next prime is 211202202112001. The reversal of 211202202112000 is 211202202112.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is not an unprimeable number, because it can be changed into a prime (211202202112001) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 568646355 + ... + 569017645.
It is an arithmetic number, because the mean of its divisors is an integer number (1395935022348).
Almost surely, 2211202202112000 is an apocalyptic number.
211202202112000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 211202202112000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (290354484648384).
211202202112000 is an abundant number, since it is smaller than the sum of its proper divisors (369506767184768).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211202202112000 is a wasteful number, since it uses less digits than its factorization.
211202202112000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 371442 (or 371410 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 211202202112000 its reverse (211202202112), we get a palindrome (211413404314112).
211202202112000 divided by its reverse (211202202112) gives a cube (1000 = 103).
It can be divided in two parts, 211202 and 202112000, that added together give a palindrome (202323202).
The spelling of 211202202112000 in words is "two hundred eleven trillion, two hundred two billion, two hundred two million, one hundred twelve thousand".
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