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211210020013 is a prime number
BaseRepresentation
bin1100010010110100011…
…0010010010010101101
3202012011120220201000211
43010231012102102231
511430024231120023
6241010055422421
721154660356046
oct3045506222255
9665146821024
10211210020013
1181634606153
1234b25984a11
1316bbc8cb805
14a318c218cd
15576269ba0d
hex312d1924ad

211210020013 has 2 divisors, whose sum is σ = 211210020014. Its totient is φ = 211210020012.

The previous prime is 211210019971. The next prime is 211210020029. The reversal of 211210020013 is 310020012112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 178816499689 + 32393520324 = 422867^2 + 179982^2 .

It is a cyclic number.

It is not a de Polignac number, because 211210020013 - 217 = 211209888941 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211210019975 and 211210020002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211210020613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605010006 + 105605010007.

It is an arithmetic number, because the mean of its divisors is an integer number (105605010007).

Almost surely, 2211210020013 is an apocalyptic number.

It is an amenable number.

211210020013 is a deficient number, since it is larger than the sum of its proper divisors (1).

211210020013 is an equidigital number, since it uses as much as digits as its factorization.

211210020013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 211210020013 its reverse (310020012112), we get a palindrome (521230032125).

The spelling of 211210020013 in words is "two hundred eleven billion, two hundred ten million, twenty thousand, thirteen".