Base | Representation |
---|---|
bin | 11110101111000011000… |
… | …001111101001010001111 |
3 | 21110220200221200022010112 |
4 | 132233003001331022033 |
5 | 234101040324341421 |
6 | 4254141422430235 |
7 | 305410555246166 |
oct | 36570301751217 |
9 | 7426627608115 |
10 | 2112101012111 |
11 | 744811a60442 |
12 | 2a140a43237b |
13 | 12422a1149bc |
14 | 74324b043dd |
15 | 39e1978c45b |
hex | 1ebc307d28f |
2112101012111 has 2 divisors, whose sum is σ = 2112101012112. Its totient is φ = 2112101012110.
The previous prime is 2112101012093. The next prime is 2112101012159. The reversal of 2112101012111 is 1112101012112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2112101012111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112101012171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056050506055 + 1056050506056.
It is an arithmetic number, because the mean of its divisors is an integer number (1056050506056).
Almost surely, 22112101012111 is an apocalyptic number.
2112101012111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112101012111 is an equidigital number, since it uses as much as digits as its factorization.
2112101012111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 2112101012111 its reverse (1112101012112), we get a palindrome (3224202024223).
Subtracting from 2112101012111 its reverse (1112101012112), we obtain a palindrome (999999999999).
The spelling of 2112101012111 in words is "two trillion, one hundred twelve billion, one hundred one million, twelve thousand, one hundred eleven".
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