21121141501301 has 2 divisors, whose sum is σ = 21121141501302. Its totient is φ = 21121141501300.

The previous prime is 21121141501261. The next prime is 21121141501303. The reversal of 21121141501301 is 10310514112112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21067861320676 + 53280180625 = 4589974^2 + 230825^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-21121141501301 is a prime.

It is a super-2 number, since 2×21121141501301² (a number of 27 digits) contains 22 as substring.

Together with 21121141501303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21121141501303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560570750650 + 10560570750651.

It is an arithmetic number, because the mean of its divisors is an integer number (10560570750651).

Almost surely, 2^{21121141501301} is an apocalyptic number.

It is an amenable number.

21121141501301 is a deficient number, since it is larger than the sum of its proper divisors (1).

21121141501301 is an equidigital number, since it uses as much as digits as its factorization.

21121141501301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 23.

Adding to 21121141501301 its reverse (10310514112112), we get a palindrome (31431655613413).

The spelling of 21121141501301 in words is "twenty-one trillion, one hundred twenty-one billion, one hundred forty-one million, five hundred one thousand, three hundred one".