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211213213122000 = 24353983132127109
BaseRepresentation
bin110000000001100011101000…
…100010100011110111010000
31000200211210012222101120021010
4300001203220202203313100
5210141004130024401000
62025114002142130520
762326436214241545
oct6001435042436720
91020753188346233
10211213213122000
11613320255435a1
121b832651880a40
1390b14222a398b
143a22aba042bcc
151964218bbbd50
hexc018e88a3dd0

211213213122000 has 320 divisors, whose sum is σ = 682185296632320. Its totient is φ = 56221558272000.

The previous prime is 211213213121879. The next prime is 211213213122071. The reversal of 211213213122000 is 221312312112.

It is a super-2 number, since 2×2112132131220002 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7791244446 + ... + 7791271554.

It is an arithmetic number, because the mean of its divisors is an integer number (2131829051976).

Almost surely, 2211213213122000 is an apocalyptic number.

211213213122000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 211213213122000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (341092648316160).

211213213122000 is an abundant number, since it is smaller than the sum of its proper divisors (470972083510320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211213213122000 is a wasteful number, since it uses less digits than its factorization.

211213213122000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29439 (or 29423 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 211213213122000 its reverse (221312312112), we get a palindrome (211434525434112).

The spelling of 211213213122000 in words is "two hundred eleven trillion, two hundred thirteen billion, two hundred thirteen million, one hundred twenty-two thousand".