Base | Representation |
---|---|
bin | 11110101111000101100… |
… | …011010100010011101111 |
3 | 21110220210220021100211012 |
4 | 132233011203110103233 |
5 | 234101132141441421 |
6 | 4254145533215435 |
7 | 305411610633620 |
oct | 36570543242357 |
9 | 7426726240735 |
10 | 2112143312111 |
11 | 744833922018 |
12 | 2a142063157b |
13 | 124235b053a1 |
14 | 7432a595a47 |
15 | 39e1d34595b |
hex | 1ebc58d44ef |
2112143312111 has 8 divisors (see below), whose sum is σ = 2436023742240. Its totient is φ = 1793799299808.
The previous prime is 2112143312093. The next prime is 2112143312119. The reversal of 2112143312111 is 1112133412112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2112143312111 - 218 = 2112143049967 is a prime.
It is a super-2 number, since 2×21121433121112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2112143312119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1384103636 + ... + 1384105161.
It is an arithmetic number, because the mean of its divisors is an integer number (304502967780).
Almost surely, 22112143312111 is an apocalyptic number.
2112143312111 is a deficient number, since it is larger than the sum of its proper divisors (323880430129).
2112143312111 is a wasteful number, since it uses less digits than its factorization.
2112143312111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2768208913.
The product of its digits is 288, while the sum is 23.
Adding to 2112143312111 its reverse (1112133412112), we get a palindrome (3224276724223).
The spelling of 2112143312111 in words is "two trillion, one hundred twelve billion, one hundred forty-three million, three hundred twelve thousand, one hundred eleven".
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