Base | Representation |
---|---|
bin | 1001100110110010110000… |
… | …10010111001101000110111 |
3 | 2202210110001222100021002111 |
4 | 10303121120102321220313 |
5 | 10232044204402331130 |
6 | 112532142552151451 |
7 | 4310111434510441 |
oct | 463313022715067 |
9 | 82713058307074 |
10 | 21124130511415 |
11 | 6804769a72448 |
12 | 2451bb8698587 |
13 | ba2cc6422819 |
14 | 5305b0415491 |
15 | 26974900802a |
hex | 1336584b9a37 |
21124130511415 has 8 divisors (see below), whose sum is σ = 25369854359328. Its totient is φ = 16885372578720.
The previous prime is 21124130511401. The next prime is 21124130511427. The reversal of 21124130511415 is 51411503142112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 21124130511415 - 231 = 21121983027767 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1741472131 + ... + 1741484260.
It is an arithmetic number, because the mean of its divisors is an integer number (3171231794916).
Almost surely, 221124130511415 is an apocalyptic number.
21124130511415 is a deficient number, since it is larger than the sum of its proper divisors (4245723847913).
21124130511415 is a wasteful number, since it uses less digits than its factorization.
21124130511415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3482957609.
The product of its (nonzero) digits is 4800, while the sum is 31.
Adding to 21124130511415 its reverse (51411503142112), we get a palindrome (72535633653527).
The spelling of 21124130511415 in words is "twenty-one trillion, one hundred twenty-four billion, one hundred thirty million, five hundred eleven thousand, four hundred fifteen".
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