Base | Representation |
---|---|
bin | 1100010011001001110… |
… | …1111011000000100111 |
3 | 202012101212102100112111 |
4 | 3010302131323000213 |
5 | 11430220311232213 |
6 | 241023034301451 |
7 | 21160133143222 |
oct | 3046235730047 |
9 | 665355370474 |
10 | 211300102183 |
11 | 81680443225 |
12 | 34b4bb87887 |
13 | 16c0547bc81 |
14 | a326b905b9 |
15 | 576a542a3d |
hex | 313277b027 |
211300102183 has 2 divisors, whose sum is σ = 211300102184. Its totient is φ = 211300102182.
The previous prime is 211300102121. The next prime is 211300102207. The reversal of 211300102183 is 381201003112.
It is a happy number.
211300102183 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211300102183 - 221 = 211298005031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211300106183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105650051091 + 105650051092.
It is an arithmetic number, because the mean of its divisors is an integer number (105650051092).
Almost surely, 2211300102183 is an apocalyptic number.
211300102183 is a deficient number, since it is larger than the sum of its proper divisors (1).
211300102183 is an equidigital number, since it uses as much as digits as its factorization.
211300102183 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 211300102183 its reverse (381201003112), we get a palindrome (592501105295).
The spelling of 211300102183 in words is "two hundred eleven billion, three hundred million, one hundred two thousand, one hundred eighty-three".
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