Base | Representation |
---|---|
bin | 10011101011011100… |
… | …100110001100100111 |
3 | 2000112120211210111222 |
4 | 103223130212030213 |
5 | 321233240331211 |
6 | 13412413250555 |
7 | 1345423063604 |
oct | 235334461447 |
9 | 60476753458 |
10 | 21130011431 |
11 | 8a63382371 |
12 | 4118493a5b |
13 | 1cb9835859 |
14 | 10463d76ab |
15 | 83a07e1db |
hex | 4eb726327 |
21130011431 has 2 divisors, whose sum is σ = 21130011432. Its totient is φ = 21130011430.
The previous prime is 21130011379. The next prime is 21130011437. The reversal of 21130011431 is 13411003112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21130011431 - 234 = 3950142247 is a prime.
It is a super-2 number, since 2×211300114312 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21130011437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10565005715 + 10565005716.
It is an arithmetic number, because the mean of its divisors is an integer number (10565005716).
Almost surely, 221130011431 is an apocalyptic number.
21130011431 is a deficient number, since it is larger than the sum of its proper divisors (1).
21130011431 is an equidigital number, since it uses as much as digits as its factorization.
21130011431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 21130011431 its reverse (13411003112), we get a palindrome (34541014543).
The spelling of 21130011431 in words is "twenty-one billion, one hundred thirty million, eleven thousand, four hundred thirty-one".
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