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211300493 is a prime number
BaseRepresentation
bin11001001100000…
…11000010001101
3112201121011210012
430212003002031
5413043103433
632544523005
75144011265
oct1446030215
9481534705
10211300493
11a9301208
125a920465
1334a12aa1
14200c47a5
151383c848
hexc98308d

211300493 has 2 divisors, whose sum is σ = 211300494. Its totient is φ = 211300492.

The previous prime is 211300489. The next prime is 211300499. The reversal of 211300493 is 394003112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 198612649 + 12687844 = 14093^2 + 3562^2 .

It is a cyclic number.

It is not a de Polignac number, because 211300493 - 22 = 211300489 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211300499) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105650246 + 105650247.

It is an arithmetic number, because the mean of its divisors is an integer number (105650247).

Almost surely, 2211300493 is an apocalyptic number.

It is an amenable number.

211300493 is a deficient number, since it is larger than the sum of its proper divisors (1).

211300493 is an equidigital number, since it uses as much as digits as its factorization.

211300493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

The square root of 211300493 is about 14536.1787619718. The cubic root of 211300493 is about 595.6166598260.

The spelling of 211300493 in words is "two hundred eleven million, three hundred thousand, four hundred ninety-three".